Question

in a parade, each tricycle and bicycle have one rider.There are 64 wheels and 28 riders.How many tricycles are there? can you show work, please

Answer 1

We can create a system of equations to represent the problem.

Let x equal the amount of bicycles there are. Let y equal the amount of tricycles there are.

x + y = 28

2x + 3y = 64

Solve x + y = 28 for "x".

x + y = 28

~Subtract y to both sides

x + y - y = 28 - y

~Simplify

x = 28 - y

Substitute (28 - y) for "x" in 2x + 3y = 64

2(28 - y) + 3y = 64

~Simplify

y + 56 = 64

~Subtract 56 to both sides

y + 56 - 56 = 64 - 56

~Simplify

y = 8

Substitute (8) for "y" in x = -y + 28

x = -8 + 28

~Simplify

x = 20

So, there were 8 tricycles and 20 bicycles.

Best of Luck!

Answer 2

Answer:

8 tricycles

Step-by-step explanation:

Make a system of equations

Let t represent tricycles, and b represent bicycles

We know that tricycles have 3 wheels, bicycles have 2, and there are a total of 64 wheels

We also know each has one rider, and there are a total of 28 riders

3t+2b=64

t+b=28

Subtract t from both sides in the second equation. This will allow us to use substitution

b= -t+28

Substitute -t+28 in for b in the first equation

3t+2b=64

3t+2(-t+28)=64

Distribute the 2

3t + 2*-t+ 2* 28 =64

3t-2t+56=64

Combine like terms

t+56=64

Subtract 56 from both sides

t=8

There were 8 tricycles