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irina [24]
3 years ago
5

Kelly tells you that when variables are in the denominator, the equation one over two plus three over x equals three over four b

ecomes unsolvable. Kelly explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to Kelly how the equation is still solvable and explain your reasoning.
Mathematics
1 answer:
olasank [31]3 years ago
8 0
1/2 + 3/x = 3/4
multiply everything by x
1/2x + 3 = 3/4x...subtract 1/2x from both sides
3 = 3/4x - 1/2x
3 = 3/4x - 2/4x
3 = 1/4x...multiply both sides by 4
4 * 3 = x
12 = x
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What is the value of the discriminant for the quadratic equation 0 = x + 2 + x^2?
aliya0001 [1]

Answer:

The discriminant of the quadratic equation is -7.

Step-by-step explanation:

We are given the following quadratic equation in the question:

x^2+x+2 = 0

Comparing to general quadratic equation:

ax^2+bx+c = 0\\a = 1\\b = 1\\c = 2

We have to find the discriminant of the quadratic equation.

Formula:

d = b^2-4ac

Putting values, we get,

d = (1)^2 - 4(1)(2) = 1 - 8 = -7

Thus, the discriminant of the quadratic equation is -7.

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If function g has the factors (x - 7) and (x + 6), what are the zeros of function g?
vagabundo [1.1K]

The zeroes of the function will be equal to ( 7, -6 ).

<h3>What is a quadratic equation?</h3>

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given function:-

  • ( x- 7 ) ( x+ 6 )

As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.

( x- 7 )  = 0

x = 7

( x+ 6 ) = 0

x = -6

Therefore zeroes of the function will be equal to ( 7, -6 ).

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Equation to find three consecutive odd integers whose sum is 3
KiRa [710]

The equation computed shows that the numbers will be 9, 11 and 13.

<h3>How to illustrate the information?</h3>

Let the numbers be:

First number = x

Second number = x + 2,

Third number = x + 4.

Total of the numbers = 33

The equation will be:

= first + second + third number

x + x + 2 + x + 4 = 33

3x + 6 = 33

Collect like terms

3x = 33 - 6

3x = 27.

Divide both side by 3

3x/3 = 27/3

x = 9

First number = x = 9

Second number = x + 2 = 9 + 2 = 11

Third number = x + 4. = 9 + 4 = 13

The numbers will be 9, 11, and 13.

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Illustrate the equation to find three consecutive odd integers whose sum is 33.

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