Question

3. The difference of the squares of two positive consecutive odd integers is 32. Find the

Answer 1

Answer:

7,9

Step-by-step explanation:

Let two consecutive odd integer=X and (X+1)

The difference of the squares of two positive consecutive odd integers is 32.

So(X+2)^2-x^2=32

(x^2+4+4x)-x^2=32

x^2+4+4x-x^2=32

4x=32-4

4x=28

X=28/4

X=7

So first integer=7

Second integer=7+2

=9.