3. The difference of the squares of two positive consecutive odd integers is 32. Find the

Mathematics

1 answer:

abruzzese [7]2 years ago

4 0

Answer:

7,9

Step-by-step explanation:

Let two consecutive odd integer=X and (X+1)

The difference of the squares of two positive consecutive odd integers is 32.

So(X+2)^2-x^2=32

(x^2+4+4x)-x^2=32

x^2+4+4x-x^2=32

4x=32-4

4x=28

X=28/4

X=7

So first integer=7

Second integer=7+2

=9.

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