The image is not attached with, but by reading the question it is obvious that the blue region lies inside the larger square and outside the smaller square. That is the region between the two squares is the blue region.
We know the dimensions of both squares, using which we can find the area of both squares. Subtracting the area of smaller square from larger one, we can find the area of blue square and further we can find the said probability.
Area of larger square = 8 x 8 = 64 in²
Area of smaller square = 2 x 2 = 4 in²
Area of blue region = 64 - 4 = 60 in²
The probability that a randomly chosen point lies within the blue region = Area of blue region/Total area available
Therefore, the probability that a point chosen at random is in the blue region = 60/64 = 0.9375
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
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Is this (1.5)2(1.5) / -2(1.5)4? or is it (1.5)2(1.5) - 2(1.5)4?
First option:
4.5/-12 = -0.375
Second option
4.5-12 = -7.5
Answer:
the answer is A
Step-by-step explanation:
Answer:
56.779 or 56.782 56.778, etc, because it has to be 8 in the hundreths thousandths less than 5 or 7 in the hundreths thousandths greater than 5
