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aev [14]
2 years ago
15

In a city, in 2011, 2,251 people were killed in motor vehicle crashes involving a distracted driver, compared to 3,715 in 2010.

Find the percent decrease from 2010 to 2011 in the number of people who were killed in crashes involving a distracted driver. Round your answer to the nearest tenth percent.
Mathematics
1 answer:
Anna35 [415]2 years ago
6 0

Answer:

It would be A decrease of 39.4%

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Can someone answer this for me ill give brainliest asap!!!!
timama [110]

Answer:

this does not have a linear function the y axes does not have a the same amount of constant change

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Step-by-step explanation:

8 0
2 years ago
103. Please help me!10 points! Thanks.
Inessa05 [86]
The formula for the surface area of a sphere is 4πr^2

This can be used in the following way, getting the diameter at 18.3:
18.3/2 = 9.15
Saying PI is 3.14 you can do this:

SA = 4*3.14*9.15^2 = 1051.6 m^2

Formula for volume is:
(4/3)πr^3

V = (4/3)*3.14*9.15^3 = 3207.2 m^3
8 0
3 years ago
What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
2 years ago
A cheese pizza costs $5. Additional toppings cost $1.50 each. Write and graph an equation in two variables that represents the t
aivan3 [116]
$6.50 I guess, because I added $5 and $1.50 and got $6.50
5 0
3 years ago
Click the picture for the question please help!!!
sesenic [268]

Answer:

297.33 m

Step-by-step explanation:

3 0
3 years ago
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