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3 years ago

What is the slope of the line on the graph ?

Mathematics

2 answers:

Tems11 [23]3 years ago

7 0

Answer:

1/2

Step-by-step explanation:

We find two points on the line

(-4,0) and (0,2)

We can find the slope using

m = (y2-y1)/(x2-x1)

=(2-0)/(0 - -4)

=(2-0)/(0+4)

= 2/4

1/2

Colt1911 [192]3 years ago

4 0

Answer:

1/2

Step-by-step explanation:

Slope is rise over run. Starting from (0, 2), go up and move right until you reach another point. So you go up 1 unit and move right 2 units.

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Find f(-4) for f(x)=9(3)^x

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Answer:

$f(-4) = \dfrac{1}{9}$

Step-by-step explanation:

$f(x) = 9(3)^x$

$f(-4) = 9(3)^{-4}$

$f(-4) = 3^2 \cdot 3^{-4}$

$f(-4) = 3^{-2}$

$f(-4) = \dfrac{1}{9}$

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4 years ago

Can someone please help me please

qwelly [4]

Answer:

$1) \dfrac{12+\sqrt{-16}}{4}=\dfrac{12+\sqrt{16i^{2}}}{4}\\\\\\=\dfrac{12+4i}{4}=\dfrac{12}{4}+\dfrac{4i}{4}\\\\\\= 3 + i$

Real part = 3 & imaginary part = 1

2) 4 + 7i - 8 = 4 -8 + 7i

= -4 + 7i

Real part = -4 & imaginary part = 7

$3)\dfrac{\sqrt{9}+\sqrt{-4}}{5}=\dfrac{3+\sqrt{4i^{2}}}{5}\\\\\\=\dfrac{3}{5}+\dfrac{2i}{5}\\\\\\Real \ part = \dfrac{3}{5} \ & \ imaginary \ part = \dfrac{2}{5}$

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Real part = -2 & imaginary part = -5

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b) 1) 6 + 4i

2) -12+ 5i

3) 5-14i

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2 years ago