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sveticcg [70]
3 years ago
8

What is the slope of the line on the graph ?

Mathematics
2 answers:
Tems11 [23]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

We find two points on the line

(-4,0) and (0,2)

We can find the slope using

m = (y2-y1)/(x2-x1)

   =(2-0)/(0 - -4)

    =(2-0)/(0+4)

    = 2/4

    1/2

Colt1911 [192]3 years ago
4 0

Answer:

1/2

Step-by-step explanation:

Slope is rise over run. Starting from (0, 2), go up and move right until you reach another point. So you go up 1 unit and move right 2 units.

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IrinaK [193]

Answer: Ok soooo you make a line graph that has 10 numbers for X and Y, then you make a line going through (1, 2 ) and then keep going for about 1-2 numbers and then your done!

Step-by-step explanation:

6 0
3 years ago
Pls help me solve pls show how you got the answer
Dmitry [639]

Polynomial 1 : x²-x²+4x -2+1 = 4x -1

Polynomial 2 : 3x-x-2x²-2+1 = -2x²+2x-1

Polynomial 3 : 4 -2x+x-x²+x²-x² = -x²-x+4

According to the question,

Polynomial 1+Polynomial2+Polynomial3 + Polynomial4 = 6x

=> 4x -1+ (-2x²+2x-1) +(-x²-x+4) + Polynomial4= 6x

=> -3x²-x+2+Polynomial4= 0

<h2>=> 3x²+x -2= Polynomial4</h2>

OPTION B

6 0
2 years ago
Read 2 more answers
Please answer correctly thank you!
Nina [5.8K]

If you rotate the triangle so that the 6 is on the bottom, the two sides are both 6.2.

Because the two sides are equal the two angles at the bottom would also be equal. One is given as 61 degrees, so the other bottom angle is also 61 degrees.

The three inside angles of a triangle need to equal 180, so X would equal 180 minus the two bottom angles.

X = 180 - 61 - 61 = 58 degrees.

5 0
3 years ago
While you are drawing with the compass the cursor comes out of the circle on the top of the compass what should you do
VikaD [51]
Try to angle it out straight
6 0
3 years ago
Which of the equations below could be the equation of this parabola?
Mademuasel [1]

Answer:

Option B: y = -\frac{1}{2} x^2

Step-by-step explanation:

The parabola has its concavity downwards, so we need a function in the model:

y = ax^2 + bx + c

With a negative value of 'a'

The vertex is (0,0), so we have that:

0 = 0a + 0b + c

c = 0

The x-coordinate of the vertex is given by the equation:

x\_vertex = -b/2a

-b/2a = 0

b = 0

So we have a function in the model:

y = ax^2

With a < 0

The only option with this format is B:

y = -\frac{1}{2} x^2

7 0
3 years ago
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