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DedPeter [7]
3 years ago
5

"jill charges an hourly rate for babysitting one or two children. kara charges a lower hourly

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer: Kara charges $14 an hour for babysitting two children

Step-by-step explanation: I did the answer follow me on

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Suppose that circles R and S have a central angle measuring 80°. Additionally, the measure of the sector for circle R is
riadik2000 [5.3K]
The correct answer is B) 9 m.

The measure of the sector of circle R is 32π/9 m.  The measure of the central angle is 80°.  This means that the sector is 80/360 = 2/9 of the circle.  The area of a circle is given by A=πr², so the area of the sector is A=2/9πr².  To verify this, 2/9π(4²) = 2/9π(16) = 32π/9.

Using this same formula for circle S, we will work backward to find the radius:

18π = 2/9πr²

Multiply both sides by 9:
18*9π = 2πr²
162π = 2πr²

Divide both sides by 2π:
162π/2π = 2πr²/2π
81 = r²

Take the square root of both sides:
√81 = √r² 
9 = r

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3 years ago
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The temperature at the center of the sun, where thermonuclear processes take place, is approximately 1. 4500 k, as shown by suns
frosja888 [35]
The answer is 3. i hope this helped
7 0
3 years ago
I need help. ill mark brain to the first to answer.
Margaret [11]

Answer:

a and f

Step-by-step explanation:

1500 is double 750, which is the combined calories of lunch and breakfast, which is only 1 third.

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Use your knowledge of scientific notation, SI prefixes, conversion factors, and
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1 x 10^10 or 10000000000
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3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg
Harman [31]

Answer:

x=\frac{-5(+/-)\sqrt{5}} {2}

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

f(x)=x^{2} +5x+5  

equate the function to zero

x^{2} +5x+5=0  

so

a=1\\b=5\\c=5

substitute in the formula

x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}

x=\frac{-5(+/-)\sqrt{5}} {2}

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

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3 years ago
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