Rewrite the right side as √3/3 = 1/√3, and recall that tan(x) = 1/√3 when x = π/6. Then since tan is π-periodic, taking the inverse tan of both sides gives
where n is any integer. Solving for x, we get
and the solutions in the interval [0, 2π] are x = 5π/6 and x = 11π/6 (for n = 1 and n = 2).
The best answer is 15/8 and it could be simplified I think
If by decomposition you mean breaking it ino parts then
break it itno 2 triangles and 1 rectangle
left to right
triangle with base y and height h
h=10
y=3
area of traignel=1/2bh
aera=1/2(10)(3)
area=5(3)
area=15
rectangel of legnth x and height h
area=legnth timwe width
x=8
h=10
area=8 times 10
aera=80
last triangle
should be same as other sinces same base (y) and same height (h)
15
add
15+80+15=120
Answer:
4 units right and 3 units up.
Step-by-step explanation:
The answer is HL. HL is a theorem stating that if the hypotenuse and one leg are congruent to another pair of hypotenuse and leg then the triangles themselves are congruent. Hope this helps.
