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REY [17]
2 years ago
11

Ron can bake 8 cookies with each scoop of flour. Write an equation that shows the relationship between the scoops of flour f and

the cookies c.
Write your answer as an equation with c first, followed by an equals sign.

please help ​
Mathematics
1 answer:
marishachu [46]2 years ago
7 0

Answer:

c = 8s

Step-by-step explanation:

One scoop of flour makes eight cookies, so

The number of cookies (c) is eight times the number of scoops (s).

The equation is

c = 8s

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Kelly has saved $35 to take music classes. She must pay a registration fee of $15 and then an additional $5 for each class. Whic
Alex Ar [27]

Answer:  

I would think 15c+5= 35 because it is the one answer that makes the most sense.  If you get this wrong I am so sorry.

5 0
2 years ago
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Well here's a picture
11Alexandr11 [23.1K]
4/5ths of 100 -of=multiply- is 80 because 4/5 = .8, .8*100 = 80 milliliters 

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2 years ago
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Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
kupik [55]
<span>If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
How would I graph

Solution:
let x= number of bracelets
    y= number of necklaces

Thus, the equation would be:
</span>$2x+$3y>200

In graphing this equation, you just have to substitute any number for the values of x and y as long as when substituted, their sum is greater than 200
8 0
3 years ago
I need help with my math to day.‍♀️
ANTONII [103]

Answer:

8x + 1 + 6x + 5 = 90

14x +  6 = 90

14x = 84

x = 6

<DCB is 6x+5

6(6) + 5

36 + 5

41

8 0
3 years ago
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