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Marina86 [1]
3 years ago
8

Currently, there are 68 of a certain endangered species in captivity. Zoologists hope to breed 5 more of the species annually. I

f x represents the number of years of breeding, which of the following equations could be used to find y, the total number of the species in captivity?
A.68y = 5x
B. y = 5x + 68
c.y = 73x
d y + 68 = 5x
Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer: B.

Step-by-step explanation: For example lets say the breeding occurs for 5 years. 5 x 5 would be 25. 25 + 68 would = 93 which is the amount of animals that are in captivity.

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Need to find volume, step by step explanation pls <br><br><br><br>​
worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

V_1=\dfrac{2}{3}\pi r^3

Where, r is the radius of the hemisphere.

V_1=\dfrac{2}{3}(3.14)(6)^3

V_1=\dfrac{6.28}{3}(216)

V_1=452.16

Volume of cylinder is:

V_2=\pi r^2h

Where, r is the radius of the cylinder and h is the height of the cylinder.

V_2=(3.14)(6)^2(12)

V_2=(3.14)(36)(12)

V_2=1356.48

We know that,

l^2=r^2+h^2                               [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

(10)^2=(6)^2+h^2

100-36=h^2

\sqrt{64}=h

8=h

Volume of cone is:

V_3=\dfrac{1}{3}\pi r^2h

Where, r is the radius of the cone and h is the height of the cone.

V_3=\dfrac{1}{3}(3.14)(6)^2(8)

V_3=\dfrac{25.12}{3}(36)

V_3=301.44

Now, the volume of the combined figure is:

V=V_1+V_2+V_3

V=452.16+1356.48+301.44

V=2110.08

Therefore, the volume of the given figure is 2110.08 cubic units.

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\leadsto f( \rm x) =  - (x - 3)(x - 5)

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