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4 years ago

7

Jared had 75 plants. Nina gave him 96 more. Choose the best way to tell how many plants Jared had. Estimate by rounding each num

ber to the nearest ten.
A) 60 + 100

B) 70 + 110

C) 60 + 110

1 answer:

coldgirl [10]4 years ago

6 0

Answer:

Anwser is A . i think

Step-by-step explanation

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I need a answer to m<br> Thanks

lara [203]

Answer:

The answer to your question is ∠Z = 119°

Step-by-step explanation:

Data

∠W = 41°

∠Y = 81°

∠Z = ∠X = ?

Process

To solve this problem use the law that states that the sum of the internal angles in a quadrangle equals 360°.

1)

∠W + ∠Y∠ + ∠X + ∠Z = 360°

2.- Simplify

∠W + ∠Y + 2∠Z = 360

3.- Substitution

41° + 81° + 2∠Z = 360

4.- Solve for Z

2∠Z = 360 - 41 - 81

2∠Z = 238

∠Z = 238/2

∠Z = 119°

3 0

3 years ago

Subtract and simplify:. . (2x2 + 5x – 4) – (3x2 – 7x + 1). . A.. –x2 + 12x – 5. . B.. –x2 – 2x – 3. . C.. 5x2 – 2x – 3. . D.. x2

Nataliya [291]

The correct answer is a

6 0

4 years ago

Plz help me its due by 11:30 today plz dont report be i want a good grade in math.

marta [7]

Answer:

(3,3) for #1

Step-by-step explanation:

Graph both equations and where they intersect is your answer

3 0

3 years ago

A 22m ladder and a 20m ladder were leaned against a building. The bottom of the longer ladder was 4m farther from the building t

OLga [1]

Answer:

Both ladder reaches 18.1 m up the building ⇒ 3rd answer

Step-by-step explanation:

* Lets study the information to solve the problem

- There are two ladders

- The lengths of them are 22 m and 20 m

- The bottom of the longer was 4 m farther than the bottom of the

shorter from the building

- Both of them reached the same distance up the building

* Lets solve the problem

- Let the distance between the bottom of the shorter ladder to the

building is x

∵ The bottom of the longer ladder is farther by 4

∴ The distance between the bottom of the longer ladder and the

building is x + 4

- Let the ladders reached the distance h up the building

* Now we have two right triangles

# Their hypotenuses are 22 and 20

# Their heights are h

# Their bases are x + 4 , x

- Lets find h in each triangle using the rule of Pythagoras

∵ (hypotenuse)² = (leg 1)² + (leg 2)²

# The longer ladder

∵ hypotenuse = 22

∵ leg 1 = x + 4

∵ leg 2 = h

∴ (22)² = (x + 4)² + h² ⇒ simplify

∴ 484 = (x + 4)² + h² ⇒ subtract (x + 4)² from both sides

∴ h² = 484 - (x + 4)² ⇒ (1)

# The shorter ladder

∵ hypotenuse = 20

∵ leg 1 = x

∵ leg 2 = h

∴ (20)² = (x )² + h² ⇒ simplify

∴ 400 = x² + h² ⇒ subtract x² from both sides

∴ h² = 400 - x² ⇒ (2)

- Equate (1) , (2) to find x

∴ 484 - (x + 4)² = 400 - x² ⇒ Add (x + 4)² and subtract 400 in both sides

∴ 84 = (x + 4)² - x² ⇒ open the bracket

∴ 84 = x² + 2(4)(x) + 4² - x² ⇒ simplify

∴ 84 = 8x + 14 ⇒ subtract 16 from both sides

∴ 68 = 8x ⇒ divide both sides by 8

∴ x = 8.5

- Substitute this value of x in (1) or (2) to find h

∵ h² = 400 - x²

∴ h² = 400 - (8.5)² = 327.75 ⇒ take √ for both sides

∴ h = 18.1

* Both ladder reaches 18.1 m up the building

4 0

3 years ago

WORTH 99 POINTS!

Ksivusya [100]

The general formula for the lateral surface area of a regular pyramid is:
$A= \frac{1}{2} *p*l$
Where:
p=perimeter of a base
l=slant height

a.
a=3ft
l=4ft
p=5*a=5*3=15ft
$A= \frac{1}{2} *15*4=30 ft^{2}$

b.
a=2.5ft
l=4ft
p=6*a=6*2.5=15ft
$A= \frac{1}{2} *15*4=30 ft^{2}$

c.
a=1.9ft
l=4ft
p=8*a=8*1.9=15.2ft
$A= \frac{1}{2} *15.2*4=30.4 ft^{2}$

d.
Based on a lateral surface area the blue umbrella is best choice. But, the best umbrella overall is the one with the greatest base area. General formula for regular polygon is:
$A= \frac{1}{4} *n* a^{2}*cot( \frac{180}{n} )$

For pentagon:
A=15.48ft^2
For hexagon:
A=16.24ft^2
For octagon:
A=17.43ft^2
Blue umbrella is still best choice.

8 0

3 years ago

Read 2 more answers