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MatroZZZ [7]
3 years ago
10

Tom is putting cartons of ice-cream in one of the freezers. There are 13 boxes and each box contains 24 cartons. How many carton

s of ice-cream are there in total?
Mathematics
2 answers:
sertanlavr [38]3 years ago
6 0

There are a total of 312 cartons or ice cream in total.

Mnenie [13.5K]3 years ago
5 0

24x13=312


There are a total of 312 total ice cream cartons.
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Jairo walked 4/10 mile on Monday. He
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he walked 1 mile

Step-by-step explanation:

we find the common denominator which is 10. 3/5=6/10

6/10+4/10=10/10 or 1 mile

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Write and solve an equation based off the verbal phrase: 6 more than x is equal to 33
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Answer:

x + 6 = 33

Step-by-step explanation:

6 more than x means there's an increment in the value of x by addition of 6

x + 6 = 33

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we subtract 6 from both sides of the equation

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Therefore, we can say 6 more than 27 is 33

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Find the values of A, B, and C in the table.<br><br> A=_____<br> B=_____<br> C=_____
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A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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