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faltersainse [42]
3 years ago
11

What is the value of the digit 1 in the number 41

Mathematics
2 answers:
Tems11 [23]3 years ago
7 0
Its in the ones place.

Gala2k [10]3 years ago
3 0
The value would be 1.
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Please help and thank you.
Ulleksa [173]

Answer:

zeros: x = 5, or (5, 0)

domain: x ≥ -4

Step-by-step explanation:

The zeros are the values of x where the graph crosses the x-axis. The graph crosses at x=5, so that is the zero.

___

The domain is the set of x-values for which the function is defined. There is no graph for x < -4, so the graph is only defined for x ≥ -4. The domain is x ≥ -4.

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The graph has the appearance of the graph of ...

y=\sqrt{x+4}-3

8 0
3 years ago
Pleaseee help quickly !!!!
lisabon 2012 [21]

Let's solve your equation step-by-step.

(− 5 /8 )(x)=−160

Step 1: Simplify both sides of the equation.

−5 /8

x=−160

Step 2: Multiply both sides by 8/(-5).

( 8 /−5 )x( −5 /8 x)=( 8/ −5 )*(−160)

x=256

Answer:

x=256

8 0
2 years ago
Solve for n (write answer only) 7/n = 4/7
harina [27]

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7 0
2 years ago
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Find the median, lower quartile, and upper quartile for the set of data.
harkovskaia [24]

\text{Find the median:}\\\\\text{To find the median, you would cross out the numbers from the side}\\\text{until you're left with the remainders. Put them in order and solve}\\\\1, 2, 4 ,5, 6, 7, 8, 9, 10, 11\\\text{Add 6 and 7 then divide by 2}\\\\6+7=13\\\\11\div2=6.5\\\\\boxed{\text{The median is 6.5}\\}\\\\\text{The lower quartile is the median of the numbers less than the median, so}\\\text{the numbers from 1-6}\\\\\text{When you cross out the numbers, you would be left with 4}

\boxed{\text{The lower quartile is 4}}\\\\\text{Do the same for the upper quartile for the numbers greater than half}\\\text{of the data set}\\\\\boxed{\text{Your upper quartile would be 9}}

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2 years ago
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I need help on 27. Please help me! Answer the 2 questions- How does the expression compare? And who has more stamps? Tell me the
Norma-Jean [14]
100+ 100+ 100+ 9= 309
200+ 50 +50= 300
Petra has more stamps
3 0
2 years ago
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