Hey there! :D
A dollar bill is worth 100 pennies.
$1.00-> .01*100 <=== same thing
When written in decimal format, each penny can be written as 100:1, because there are 100 pennies in a dollar. One penny would just be one out of 100.
I hope this helps!
~kaikers
Answer:
(29.14 ; 30.06)
Step-by-step explanation:
Given that'
Sample size (n) = 57
Mean (m) = 29.6
Population standard deviation (σ) = 2.7
Confidence interval = 80%
= (1 - 0.8) / 2 = 0.1
Mean ± z * σ/√n
Using the Z probability calculator : Z0. 1 = 1.28
Hence,
29.6 ± 1.28 * (2.7 / √57)
29.6 - (1.28 * 0.3576237) ; 29.6 + (1.28 * 0.3576237)
29.142241664 ; 30.057758336
(29.14 ; 30.06)
Answer:
-28
Step-by-step explanation:
-16 +(-12)
= -16 - 12
adding both of them,
= - 28
Answer:
Step-by-step explanation:
Given that:
The numbers of the possible public swimming pools are 5
From past results, we have 0.007 probability of finding bacteria in a public swimming area.
In the public swimming pool, the probability of not finding bacteria = 1 - 0.007
= 0.993
Thus;
Probability of combined = Probability that at least one public
sample with bacteria swimming area have bacteria
Probability of combined sample with bacteria = 1 - P(none out of 5 has
bacteria)
Probability of combined sample with bacteria = 1 - (0.993)⁵
= 1 - 0.9655
= 0.0345
Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345
From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.
Thus, we can conclude that; Yes, the probability is low enough that there is a need for further testing.