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2 years ago

Sum term product factor quotients coefficients for 5x+12

Mathematics

1 answer:

Svetllana [295]2 years ago

4 0

I tried I hope this helps in any kind of way

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Solve the inequality for x. 75+15x is greater than or equal to 140

Gre4nikov [31]

75+ 15x ≥ 140
⇒ 15x ≥ 140 -75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3

The final answer is x ≥ 4 1/3~

8 0

2 years ago

The size of the largest angle in a triangle is 3 times the size of the smallest angle.

prohojiy [21]

Answer:

a = 29

b = 64

c = 87

Step-by-step explanation:

Let the angles be a (smallest), b, and c (largest).

We know that a triangle's angles must add up to 180 degrees, so we can construct the following equations.

a + b + c = 180

c = 3a

b = a +35

With some solving and substitution...

a + (a + 35) + c = 180

2a + c = 145

2a + (3a) = 145

5a = 145

a = 29

and therefore,

b = 29 + 35 = 64

c = 3(29) = 87

6 0

2 years ago

Read 2 more answers

Which one of the relationships described is not proportional?

ivann1987 [24]

Answer:

Marianne is 15 years old and her brother is 5 years old; is the relationship between their ages proportional?

Step-by-step explanation:

i just did it

8 0

2 years ago

Which expression is equivalent to (4 × 8) + (4 × 3)?

bixtya [17]

Answer:

Step-by-step explanation:

(4 x 8) + (4 x 3)=44

4 x (8 + 3)=44

3 0

1 year ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago