Answer:
Therefore there total of 39 children presented in group of people who attended a ball game.
Step-by-step explanation:
Given:
Total people present=52 .
And there are 3 times children as adults
To Find:
No.of Children Present in Group.
Solution:
<em>Consider 'x' be the children and 'y' be Adults presented in group.</em>
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So there are total of 52 people.
Therefore Equation becomes,
x+y=52.
And also there are 3 times children presented in group as adults were.
So
Children=3 times adults
i.e.x=3y
Using in above Equation we get ,
x+y=52
3y+y=52
4y=52
y=52/4
y=13
Hence there are 13 adults presented in group
So ,
No.of Children=x=3y
=3(13)
=39
No.of.Children =39
Answer: 560
Step-by-step explanation:
There are [20, 22, 24, 26, 28]: 5 even integers for each ten numbers.
The 20's set can be written as 5*20 + (2+4 + 6 + 8) = 5*20 + (20) = 120
The 30's can be written: 5*30 + 20 = 170
40's: 5*40+20 = 220
50's: 5*50+20 = 270
60's: 5*60+20 = 320
Each set is incremented by 50
We want the sets for 20, 30, and 40, plus the number 50.
(120+170+220+50) = 560
You can also do this in Excel (attached). Set the first cell to 20, the next cell below equal to the cell above plus 2. Then draw the second cell down until you've reached 50. Then sum the cells to arrive at 560.
divide 3 by 4 = 3/4 = 0.75
so Cody jogs 3/4 mile for every 1 mile Vanessa runs
D 85try telling me what like operation it would be so be easier to figure out