Answer:
A. 1
B. 
.
Step-by-step explanation:
We have been given an equation of a line 
.
A. We know that slope of parallel lines is always equal,
We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.
B. We know that the product of slopes of two perpendicular lines is .
Let m represent slope of perpendicular to our given line, then:
Therefore the slope of the line perpendicular to our given line would be .
Answer:2460
Step-by-step explanation:
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Answer:
(- 1, 2)
Step-by-step explanation:
Given a quadratic in standard form y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= - 
f(x) = x² + 2x + 3 ← is in standard form
with a = 1 and b = 2, hence
= - 
= - 1
Substitute x = - 1 into f(x) for corresponding value of y
f(- 1) = (- 1)² + 2(- 1) + 3 = 1 - 2 + 3 = 2
vertex = (- 1, 2 )
