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Umnica [9.8K]
3 years ago
12

I need help I don’t know this question

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0
So singlehandedly, November has 25% of the total rain in one year of New York's, which is 62.51 inches.

So, November receives: *percentage* x *total*
= 25% x 62.51 = 15.6275 in

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So, in November, New Yorks receives 25% of total rain in one year, which is 15.6275 inches.
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I'd like my Brainliest pls ;W;
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3 years ago
Nu is designing a rectangular sandbox.The bottomm is 16 square feet.Which dimensions require the least amount of materail for th
zzz [600]

Given Information:  

Area of rectangle = 16 square feet

Required Information:  

Least amount of material = ?

Answer:

x = 4 ft and y = 4 ft

Step-by-step explanation:

We know that a rectangle has area = xy and perimeter = 2x + 2y

We want to use least amount of material to design the sandbox which means we want to minimize the perimeter which can be done by taking the derivative of perimeter and then setting it equal to 0.

So we have

xy = 16  

y = 16/x

p = 2x + 2y

put the value of y into the equation of perimeter

p = 2x + 2(16/x)

p = 2x + 32/x

Take derivative with respect to x

d/dt (2x + 32/x)

2 - 32/x²

set the derivative equal to zero to minimize the perimeter

2 - 32/x² = 0

32/x² = 2

x² = 32/2

x² = 16

x = \sqrt{16} = 4 ft

put the value of x into equation xy = 16

(4)y = 16

y = 16/4

y = 4 ft

So the dimensions are x = 4 ft and y = 4 ft in order to use least amount of material.

Verification:

xy = 16

4*4 = 16

16 = 16 (satisfied)

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Which of the numbers listed below are solutions to the equation?
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Simplify the expression where possible. (6^3)^-3
astraxan [27]

\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
(6^3)^{-3}\implies 6^{-3\cdot 3}\implies 6^{-9}\implies \cfrac{1}{6^9}\implies \cfrac{1}{10077696}

3 0
3 years ago
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