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Finger [1]
3 years ago
13

2,930,000

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

WHAT

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Step-by-step explanation:

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Simplify the expression 200y+30+110-75y×2+y
vichka [17]
The answer would be 51y+140
4 0
3 years ago
Find a_4 and a_n for the arithmetic sequence. a_6= -15, a_8= -7 <br> .
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Stardust the unicorn, covered a distance of 50 miles on his first trip to the forest. On a later trip he travelled 300 miles whi
timama [110]
For this case, the first thing we must take into account is the following definition:
 d = v * t
 Where,
 d: distance
 v: speed
 t: time
 Substituting values we have:
 Trip 1:
 
50 = v * t1
 We cleared t1:
 t2 = (50) * (1 / v)
 Trip 2:
 
300 = (3 * v) * t2
 We cleared t2:
 t2 = (300/3) * (1 / v)
 t2 = (100) * (1 / v)
 Rewriting:
 t2 = 2 (50) * (1 / v)
 t2 = 2 * t1
 Answer:
 
His new time compared with the old time was:
 
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4 0
3 years ago
If EG=50,and point F is 2/5 of the way between E and G
TEA [102]
2/5 of 50 is 20. 50-20=30. Making FG=30

7 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
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