Find a common denominator 7/8 = 35/40 and 5/10 = 20/40. Also 7/8 is almost a whole and 5/10 is half. 7/8 is greater.
Answer:
2%
Step-by-step explanation:
Let x be the first number
It increases by 70 %
The new number is
m = x+ .70x
= 1.7x
Let y be the second number
It decreases by 40 %
The new number is
n =y - .40 y
= .6y
The product of the original numbers is xy
The product of the new number is
mn = (1.7x * .6y) = 1.02xy
The new number is larger than the old number so it is an increase.
Percent increase is new - original divided by original times 100%
Percent increase = (1.02 xy - xy)
----------------- * 100%
xy
= .02 xy
------- * 100 %
xy
= .02 * 100 %
= 2%
Answer:
x = 3, x = 4
Step-by-step explanation:
Given
= 14 - 2x ( multiply through by x , x ≠ 0 )
24 = 14x - 2x² ( subtract 14x - 2x² from both sides )
2x² - 14x + 24 = 0 ( divide through by 2 )
x² - 7x + 12 = 0 ← in standard form
(x - 3)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 3 = 0 ⇒ x = 3
x - 4 = 0 ⇒ x = 4
Answer:
The answer is B hope this helps!!
Step-by-step explanation:
Answer:
Step-by-step explanation:
First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.
Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.
-4.9t^2+7.5t+-.3=0
Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.
The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.
(-b±sqrt(b^2-4ac))/(2a)
(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)
(-7.5±sqrt(56.25-5.88))/(.9.8)
(-7.5±sqrt(50.37))/(-9.8)
(-7.5±7.097)/(-9.8)
The plus or minus means there are two equations.
(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.
.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.
