Question

An airplane needs to head due north, but there is a wind blowing from the northeast at 50 km/hr. The plane flies at an airspeed of 700 km/hr, To end up due north, the pilot will need to fly the plane Preview degrees east of north.

Answer 1

Answer:$\theta =2.415^{\circ}$

Step-by-step explanation:

Using vector method to solve it

Resultant can be given by

$R^2=700^2+40^2+2\times 700\times 40cos135$

$R^2=450,408$

R=671.12 Km/hr

The angle made by resultant with 700 km/hr is $\theta$

using sine rule

$\frac{40}{sin\theat }=\frac{R}{sin45}$

$sin\theta =0.0421509$

$\theta =2.415^{\circ}$