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Olegator [25]
3 years ago
5

A regular octagon has an apothem measuring 10 in. and a perimeter of 66.3 in.

Mathematics
1 answer:
Leni [432]3 years ago
4 0

Answer: 331.5 inches²

Step-by-step explanation:

To solve for the area of a regular octagon, we can use the formula that is shown below:

Area = 1/2 × apothem × perimeter

In this problem, we have been given the following values:

Apothem = 10 inches

Perimeter = 66.3 inches

To solve for the area,

Area = 1/2 × apothem × perimeter

Area = 1/2 × 10 × 66.3

Area = 331.5 inches²

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3 years ago
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Answer:

The focus point is (2 , 0) ⇒ answer D

Step-by-step explanation:

* Lets revise the equation of the parabola in standard form

- The standard form is (x - h)² = 4p(y - k)

- The focus is (h, k + p)

- The directrix is y = k - p

- If the parabola is rotated so that its vertex is (h , k) and its axis of

 symmetry is parallel to the x-axis, it has an equation of

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- The focus is (h + p, k)

- The directrix is x = h - p

* Lets solve the problem

∵ The equation of the parabola is y = 1/8(x² - 4x - 12)

- Lets make x² - 4x completing square

∵ √x² = x  

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∵ 4x ÷ 2 = 2x

∴ The product of the 1st term and the 2nd term is 2x

∵ The 1st term is x

∴ the second term = 2x ÷ x = 2

∴ The bracket is (x - 2)²

∵  (x - 2)² = (x² - 4x + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out  

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∴ (x² - 4x + 4) - 4 = (x - 2)² - 4

- Lets put the equation after making the completing square

∴ y = 1/8 [(x - 2)² - 4 - 12]

∴ y = 1/8 [(x - 2)² - 16] ⇒ multiply both sides by 8

∴ 8y = (x - 2)² - 16 ⇒ add 16 to both sides

∴ 8y + 16 = (x - 2)² ⇒ take from the left side 8 as a common factor

∴ 8(y + 2) = (x - 2)²

∴ The standard form of the equation of the parabola is

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∵ The standard form of the equation is (x - h)² = 4p(y - k)

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∵ 4p = 8 ⇒ divide both sides by 4

∴ p = 2

∴ The focus = (2 , -2 + 2) = (2 , 0)

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Answer: Table A

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The coefficient of x^2 is 1, the coefficient of x is -6, and the constant is 0. This means that a = 1, b = -6, and c = 0.

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Now, we need to determine if the graph opens up or down to differentiate between A and B. Since the coefficient of x^2 is positive, the graph opens up.

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