Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
So there are 6 different grade levels with 3 classes in each. So 6*3 = 18 classes total.
<span>If there are approximately 27 children in each class, than 27*18 = ? your answer.</span>
Hi. Here it is!
I hope this help...
—> And the answer is letter A
