Based on the scenario, the reduced form of f(n) is :
f(n) = n^4/4+n^3 + 5n^2/4+n/2
or, it could also be written as
n/4 (n+1) (n^2 + 3n + 2)
hope this helps
Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
Given:
M is the mid-point of RS
N is the mid-point of ST
MN = 18.4
To find:
The length of RT.
Solution:
The reference image is attached below.
Joining mid-point M and N, we get mid-segment MN.
MN is parallel to RT.
Triangle mid-segment theorem:
If a segments joins the mid point of a two sides of triangle, then the segment is parallel to the third side and is half of that side.
Substitute MN = 18.4
Multiply by 2 on both sides.
The length of RT is 36.8.
Answer: -30
Step-by-step explanation: -13 subtract 17 = -30
