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Natali [406]
3 years ago
12

Which value of b would make x²+bx-30 factorable? A. -31 B. -17 C. 11 D. 13

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0
I think the answer is. D 14
dimulka [17.4K]3 years ago
5 0

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b±\sqrt{b^{2}-4ac} /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since \sqrt{13^{2}-4*1*(-30) = \sqrt{289} = 17. So b=13.

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The sum of the sequence of 685+678+671+664+...+6
lukranit [14]

Answer:

Sum of the sequence (Sn) = 33,859

Step-by-step explanation:

Given:

Sequence = 685+678+671+664+...+6

Find:

Sum of the sequence (Sn)

Computation:

a = 685

d = 678 - 985 = -7

an = 6

an = a+(n-1)d

6 = 685+(n-1)(-7)

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97 = n-1

n = 98

So,

Sum of the sequence (Sn) = (n/2)[a+an]

Sum of the sequence (Sn) = (98/2)[685+6]

Sum of the sequence (Sn) = (49)(691)

Sum of the sequence (Sn) = 33,859

3 0
3 years ago
A number is selected from the set (1, 2, 3, 5, 15, 21, 29, 38, 500). If equal elemental probabilities are assigned, what is
Katen [24]

Answer:

\frac{7}{9} OR 77.78%

Step-by-step explanation:

So, we first need to find out how many numbers fit the "less than 29 or odd" group.

This would be: 1, 2, 3, 5, 15, 21, and 29, which is a total of 7 numbers.

Next, we figure out the total amount of numbers in the population.

This would be: 1, 2, 3, 5, 15, 21, 29, 38, and 500, which is a total of 9 numbers.

Finally, we put the first number (7) over the total (9) = \frac{7}{9}

\frac{7}{9} is now able to be written in a percentage, if you need.

The probability is \frac{7}{9} OR 77.78%

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3 years ago
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