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skelet666 [1.2K]
3 years ago
11

Movement Which Portuguese explorer stayed closer to land?

Social Studies
2 answers:
pochemuha3 years ago
7 0

Answer:

Portuguese discoveries (Portuguese: Descobrimentos portugueses) are the numerous territories and maritime routes discovered by the Portuguese as a result of their intensive maritime exploration during the 15th and 16th centuries. Portuguese sailors were at the vanguard of European overseas exploration, discovering and mapping the coasts of Africa, Canada, Asia, and Brazil, in what became known as the Age of Discovery. Methodical expeditions started in 1419 along West Africa's coast under the sponsorship of prince Henry the Navigator, with Bartolomeu Dias reaching the Cape of Good Hope and entering the Indian Ocean in 1488. Ten years later, in 1498, Vasco da Gama led the first fleet around Africa to India, arriving in Calicut and starting a maritime route from Portugal to India. Portuguese explorations then proceeded to southeast Asia, where they reached Japan in 1542, forty-four years after their first arrival in India. In 1500, the Portuguese nobleman Pedro Álvares Cabral became the first European to discover Brazil.

Explanation:

gayaneshka [121]3 years ago
6 0
Answer:
Vasco da Gama
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What is your personal definition of learning? How do your ideas about learning compare with the definition of learning presented
algol [13]

Answer:

The answer to this question, and especially the text that your question aludes to, can be found on the lumenlearning website, and it says this: that all beings have a three-step process of learning that explains how an organism develops the capacities to behave and act accordingly, depending on the conditions around it. These three steps are: classical conditioning (Pavlovian conditioning), operant conditioning, and finally, observation. All organisms go through these steps to learn how to behave and act in an environment.

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Explanation:

4 0
3 years ago
The equation f(x) is given as x2 – 4 = 0. Considering the
valentina_108 [34]

Answer:

The correct answer is "\frac{10}{3}".

Explanation:

The given function is:

f(x)=x^2-4=0

and,

x_0=6

By differentiating with the help of Newton's Raphson method, we get

⇒ x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

then,

⇒ x_1=x_0-\frac{f(x_0)}{f'(x_0)}

        =6-\frac{f(6)}{f'(6)}

        =6-\frac{(6)^2-4}{2\times 6}

        =6-\frac{8}{3}

        =\frac{10}{3}  

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