Let x be a random variable representing the mean saraly of professors at two year institutions, then
P(x > 55000) = 1 - P(z < (55000 - 52500)/4000) = 1 - P(z < 0.625) = 1 - 0.73401 = 0.26599
8.75 times
Hope this helps
Ty
h(t) = -16t² + 50t + 5
The maximum height is the y vertex of this parabola.
Vertex = (-b/2a, -Δ/4a)
The y vertex is -Δ/4a
So,
The maxium height is -Δ/4a
Δ = b² - 4.a.c
Δ = 50² - 4.(-16).5
Δ = 2500 + 320
Δ = 2820
H = -2820/4.(-16)
H = -2820/-64
H = 2820/64
H = 44.0625
So, the maxium height the ball will reach is 44.0625
Let us say that,
<span>A = perimeter of football field of the 1st
school</span>
B = perimeter of football field of the 2nd school
C = perimeter of football field of the 3rd school
So that:
A = 320 m
B = 360 m
C = 400 m
So the first thing we have to do to find for the minimum
laps to make is to divide every perimeter by the smallest one, therefore divide
all by 320 m, hence:
A’ = 1
B’ = 1.125
C’ = 1.25
Now multiply everything by a number such that all laps
will be a whole number, in this case multiply everything by 8:
A’ = 8
B’ = 9
C’ = 10
Hence the laps to run are:
<span>8, 9 and 10</span>
Answer:
Volume = 3.15 cm³
Step-by-step explanation:
mass = 5 gram
density = 1.59 g/cm³
now
density = mass/ volume
or, 1.59 = 5/v
or, v = 5/1.59
so, v = 3.15 cm³