All categories

3 years ago

X2 + 12x + 27 completely.

Mathematics

2 answers:

kap26 [50]3 years ago

8 0

the answer is a

a is the answer

bulgar [2K]3 years ago

7 0

I’m pretty sure it’s A.

You might be interested in

Which statement best describes the area of Triangle ABC shown below?

PolarNik [594]

Answer:

it is half the area of a square of side length 8

Step-by-step explanation:

area of a square = l × b

= 8 × 8

= 64 cm^2

area of a triangle = b × h ÷ 2

= 8 × 8 ÷ 2

= 64 ÷ 2

= 32 cm^2

hope you can understand ☆☆☆

8 0

3 years ago

Need to show my work

dalvyx [7]

Answer:

$\large\boxed{x=\dfrac{5}{4},\ y=\dfrac{15}{16}}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=\dfrac{3}{4}x&(1)\\\dfrac{5}{2}x+2y=5&(2)\end{array}\right\\\\\text{Substitute}\ (1)\ \text{to}\ (2):\\\\\dfrac{5}{2}x+2\left(\dfrac{3}{4}x\right)=5\\\\\dfrac{5}{2}x+\dfrac{3}{2}x=5\\\\\dfrac{5+3}{2}x=5\\\\\dfrac{8}{2}x=5\\\\4x=5\qquad\text{divide both sides by 4}\\\\x=\dfrac{5}{4}$

$\text{Put the value of}\ x\ \text{to (1)}\\\\y=\dfrac{3}{4}\cdot\dfrac{5}{4}\\\\y=\dfrac{15}{16}$

4 0

4 years ago

Read 2 more answers

Please help i’ll give brainliest

Ahat [919]

Answer:

Carla is correct

Step-by-step explanation:

When you multiple or divide a negative the sign changes, or flips the other side.

ex:-4x≥12

-4x/-4≥12/-4

x≤-3

hope this helps!

5 0

3 years ago

Read 2 more answers

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

4 years ago

Plz help i suck art math

True [87]

um 600?? I'm sorry if that's wrong

5 0

3 years ago

Read 2 more answers