594 miles in 9 hours

Which expression is equivalent to -1.3-(-1.9)

alex41 [277]

-1.3+1.9=.6
the two minus signs turn into a plus so you add 1.9 to -1.3

7 0

2 years ago

The following table shows the speeds at which Jeff does 4 activities. For example, biking has a rate of 19 miles in 2 hours. Whi

ExtremeBDS [4]

The type of activity that Jeff does at a speed of 4.5 miles per hour is Swimming

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<em>This problem is about Kinematics.</em>

We will solve it in the following way

$\texttt{Speed of Biking} = \texttt{Distance of Biking} \div \texttt{Time Taken}$

$\texttt{Speed of Biking} = \texttt{19} \div \texttt{2}$

$\texttt{Speed of Biking} = 9.5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Walking} = \texttt{Distance of Walking} \div \texttt{Time Taken}$

$\texttt{Speed of Walking} = \texttt{14} \div \texttt{4}$

$\texttt{Speed of Walking} = 3.5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Running} = \texttt{Distance of Running} \div \texttt{Time Taken}$

$\texttt{Speed of Running} = \texttt{15} \div \texttt{3}$

$\texttt{Speed of Running} = 5 \texttt{ miles per hour}$

$\texttt{ }$

$\texttt{Speed of Swimming} = \texttt{Distance of Swimming} \div \texttt{Time Taken}$

$\texttt{Speed of Swimming} = \texttt{18} \div \texttt{4}$

$\texttt{Speed of Swimming} = \boxed{4.5 \texttt{ miles per hour}}$

$\texttt{ }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

3 0

2 years ago

Read 2 more answers

A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.63 m/s. Four seconds later,

castortr0y [4]

From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s)*t.

The bicyclist covers a distance of 1/2*(2.11 m/s^2)*t^2. They meet when these distances are equal:

3.63 t = 1.055 t^2 ==> 1.055 t^2 - 3.63 t = 0

==> t = 0 s or t = 3.44 s

5 0

2 years ago

What is the area of 71 length and 27 width of the triangle??

vazorg [7]

The area of this triangle is 958.5 units^2

8 0

3 years ago

Am I right or wrong can you let me know so i can know if im doing it the right way

GarryVolchara [31]

Answer:

you are right

Step-by-step explanation:

great job

5 0

2 years ago