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3 years ago

6

One half of the students in a school are girls, 3/5 of these girls are studying in lower classes. What fraction of girls are stu

dying in lower classes?

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

4

Step-by-step explanation:

4

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You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?

Vladimir79 [104]

The first cube can land in any one of 6 ways.
The second cube can land in any one of 6 ways.
Total number of ways that 2 dice can land = (6 x 6) = 36 ways.

For any of these ways, the sum of the numbers rolled is 9 :

3, 6
4, 5
5, 4
6, 3

There are 4 ways to roll a 9, out of a total of 36 ways that
the dice can land. So the probability of rolling a 9 is

4 / 36 = 1 / 9 = <em>11-1/9 percent</em>

7 0

3 years ago

PLZ HELP ILL MARK AS BRAINLIEST

Rainbow [258]

Answer:

1092 cm^2

Step-by-step explanation:

Formula = 2 * Height (Length + Width)

2 * 26 (15 + 6) = 1092

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3 years ago

Plant A is 16/3 feet tall plant C is 4/5 as tall as plant a how tall is plant

melisa1 [442]

Answer:

13

Step-by-step explanation:

Multiply 16 by 12 = 192
Add 3 = 195
80% Of 195 = 156
156 / 12 = 13
13 feet

3 0

2 years ago

Read 2 more answers

The sum of two integers is 51. The larger number is 3 more than 5 times the smaller number. Find the value of the larger number

Alona [7]

Answer:

Larger number = 43

Step-by-step explanation:

Smaller number = x

Larger number = 5x + 3

Sum of two integers = 51

x + 5x + 3 = 51

6x + 3 = 51

6x = 51-3

6x = 48

x = 48/6

x = 8

Larger number = 5x + 3

= 5*8 + 3

= 40 + 3

= 43

5 0

3 years ago

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

<u>Case a)</u> $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

so

the case a) have the same solution that the given equation

<u>Case b)</u> $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

so

the case b) have the same solution that the given equation

<u>Case c)</u> $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

<u>Case d)</u> $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

so

the case d) have the same solution that the given equation

<u>Case e)</u> $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

<u>the answer is</u>

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

7 0

4 years ago

Read 2 more answers