Answer:
add all of them together (x and y’s) the divide the sum by the amt of numbers
Step-by-step explanation:
I got 65/153 since you actually multiply by the reciprocal of the second fraction.
Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
Answer:
Its actually one solution it is solvable and only has one solution
Step-by-step explanation:
16x + 33y = 260, I think this is correct. Hope this helps!:)
