Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
<span>Decreasing on the interval of -∞<x<0
</span>When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than <span>f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than </span><span>f(x)=|x|
- When A turns negative, it flips the graph upside down.
-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left
When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards</span>
First we have to assume that each quarter touched each other. Hence the area of the table not covered by the coins (A) is equal to the total area of the table (At) minus the total area of the coins (Ac). Coins are circle, so
and r =24.26mm. The area of one coin is then 1848.98mm^2. Hence the equation is A = At - xAc where x is the number of coins.
Answer:
just by looking at the graph you can see that the y int is one, so that eliminates two answers already. Then the slope is rise over run. (best thing to remember in math. rise over run) so pick two points. (0, 1) and (4,0) were the first ones i saw. to get from those two points you go from (0,1) over 4 (thats your run) and from there down 1 (thats your rise) to get to (0,4). You would then do rise over run (and because your rise goes down its negative) to get -1/4 as your slope. The answer is slope= -1/4, Y intercept = 1
I believe the answer is 45.
In the research, the distribution is described by its shape. If there are more higher values than lower values, the distribution is skewed left.
<h3>How to illustrate the research?</h3>
It should be noted that when the distribution of data is skewed to the <u>left</u>, the mean is less than the median.
The distribution can be described by its center. If the distribution is skewed left or right, the <u>median</u> is an accurate measure of center.
The distribution can be described by its spread. If the data set does not have an outlier, the interquartile range is an accurate measure of spread.
Learn more about research on:
brainly.com/question/25257347
