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Phantasy [73]
3 years ago
11

7 − 3x + 3 + 8x combining like terms

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

10+5x

Step-by-step explanation:

7 and 3 are like terms and 7+3=10

-3x and 8x are also like terms and -3x+8x=5x

Therefore you have 10+5x

Darya [45]3 years ago
5 0

Answer:

10-11x

Your welcome

Step-by-step explanation:

First, sort out the variables and the non-variables:

(7+3)-(8x+3x)

Then add the variables and the non-variables:

10-11x

Your Welcome

(I am 99.9% sure this is right)

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german

Answer:

A hostel has provision for 45 students for 30 days.If 15 more students joined the hostel after 6 days,how long will provision last?

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3 years ago
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Can someone plzzz help me with this math practice paper
weeeeeb [17]

Answer:

45 degrees for 8

135 degrees for 9

48 for 10

Yes a square is a rectangle

Next ones.

Sut = 21 becuase x=5

7

Step-by-step explanation:

Last one:

x^2 + 8 = 3x + 36

      - 8          -  8

x^2        = 3x + 28

     -3x       -3x

x^2 - 3x =     28

(x · x) - 3x = 28.        

This was were a little guess work was used,

I found that any number lower than 7 is less than 28 when pluged into x and any above is higher.

Hence x = 7

So

x^2 + 8 = 7^2 + 8

7 x 7 = 49.    49 + 8 = 57.

and

3x+36 = 7 x 3 + 36

7x3 = 21. 21 + 36 = 57.

Both lines are equal so x is indeed 7.

The RSTU rectangle

3x+6 = 5x-4

    +4        +4

3x+10 = 5x

-3x        -3x

10 = 2x

10/2 = 5

5 = x or x = 5

plug it in now

3 x 5 = 15. 15 + 6 = 21

and

5 x 5 = 25. 25 - 4 = 21

so x = 5

8-10

QRS = 45 degrees because bisects the square with a diagonal line from corner to corner

PTQ is a 135 degrees because it is wider than a 90 degrees angle and meets both upper corner from the middle of the square making it 135 degrees.

SQ = 48 because RT = 24 and RT is half the length of SQ meaning its length would be 48

Or

SQ= 24 degrees because RT = 24 and if RT was to continue on the line it is on it will reach the length of SQ.

3 0
3 years ago
Twelve less than a number is -75
yanalaym [24]
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3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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3 years ago
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