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Anna007 [38]
3 years ago
11

Read the attachment and complete the question in the attachment

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0
I am pretty sure the answer is c

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Graph the following quadratic equation<br> f (x) = x² - 4x + 3
PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

5 0
2 years ago
What is the center and radius of the circle?
Setler79 [48]
I believe the answer should be B. Because of the standard circle equation.
5 0
3 years ago
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I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
At the circus, a clown is shot from a cannon. This situation can be modeled by the function: h = – 16t2 + 45t + 15, where 'h' is
weeeeeb [17]

Answer:

The maximum height is 46.64 feet.

Step-by-step explanation:

If we take the derivative of h whit respect to t and equal this to zero we would find the value of t which corresponds to the maximum h.

So, we have the function h(t):

h(t)=-16t^{2} + 45t + 15

Taking the derivative, we have:

\frac{dh(t)}{dt}=-32t + 45=0

Now, we solve it for t:

t=\frac{45}{32}=1.4\: s

Finally, we put this value of t into the original equation.

h(t)=-16(1.4)^{2} + 45(1.4) + 15

h_{max}=46.64\: ft      

Therefore, the maximum height is 46.64 feet. All the given options are wrong, the one that comes closest is option A.

I hope it helps you!          

4 0
3 years ago
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