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AlladinOne [14]
3 years ago
8

Hold on guys my sister needs an answer I am on a call pls help

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0

Answer:

d=27

Step-by-step explanation:

14+8 = 22

22 + 5 = 27

Olenka [21]3 years ago
3 0

Answer:

they had 27 dogs at the shelter

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What is the solution to 7 × p = -56? A. -49 B. -8 C. 8 D. 49
Serga [27]

Answer:

-8

Step-by-step explanation:

Hello!

What we do to one side of the equation we do to the other side

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Hope this helps!

4 0
3 years ago
What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

6 0
3 years ago
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yaroslaw [1]
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3 years ago
How many cups of flour are needed if we increase the recipe by 50%?
TEA [102]

Answer:it is 2

Step-by-step explanation:

4 0
3 years ago
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