Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
X^3 -9x+1= 0 (minus 1)
X^3-9x=-1 (divide by 9)
x^3-x=-1/9
But it doesn’t work any further so you have written it wrong
Answer:
-10=x1 -17=y1
-8=x2 -15.7=y2
formula:
y2 -y1
_____ =m
x2-x1
y1=m(x1)+b
Step-by-step explanation:
X=4. If k is the midpoint then JK is equal to KL. Since JK is 7 then KL is also 7 meaning JK is 14. JK is represented by the expression 4x-2 so you just set that expression equal to 14 and solve for x. Hope this helped!
A:b = 4:5
b:c=3:2
b was 5 then it was 3, so you have to find the common multiple which is 15.
you’d have to times the 4 (a) by 3 since that 5x3 is 15
you’d have to times the 2 (c) by 5 since 5x3 is 15 again.
therefore the answer would be
a:b:c
12:15:10
I hope this makes sense it was kinda hard to explain sorry :)
