Answer:
If it is less than 3, Player 1 earns 3 points.
If not, Player 2 earns 2 points.
Step-by-step explanation:
<u>Player 1</u> :
p(N < 3) = p(N = 1 or N = 2) = 2/5
<u>Player 2</u> :
p(N ≥ 3) = p(N = 3 or N = 4 or N = 5) = 3/5
<u>We notice that</u> :
p(N < 3) × 3 = (2/5) × 3 = 6/5
On the other hand,
p(N ≥ 3) × 2 = (3/5) × 2 = 6/5
since ,the probability player 1 win multiplied by the associated number of points (3)
is equal to
the probability player 2 win multiplied by the associated number of points (2).
Then the game is fair.
Let x be the number of running plays
Y be the number of
passing plays
Since the total plays is 110
X + y = 110
And total yard is 378
3x + 7y = 378
Using the first equation
X = 110 – y and substitute to the 2nd equation
3(110 – y) + 7y = 378
And solve for y
Y = 12
Substitute to eqution 1
X = 110 – 12 = 98
Hello there.!
<span>Does anybody know this answer ??6x-12 2x=3x 8x-15
</span><span>0.35775</span>
