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Mariana [72]
3 years ago
6

What are the domain and range of the logarithmic function f(x) = log7x? Use the inverse function to justify your answers.

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

Answer:


Step-by-step explanation:

Since log is defined by all positive real  numbers

therefore domain is all  positive real number that is ( 0,∞)

Range is given by real numbers

inverse of the given function is  (10^x)/7

Whose domain is all real numbers and range is all positive real number

And since we know that domain of function and range of its inverse

& range of a function and domain of its inverse is same

which we are getting in the problem

so  answer is justified

liraira [26]3 years ago
5 0

Answer:    


Step-by-step explanation: The domain of a function is the set of all values for which the function is defined and the range is the set of all values y, for which there exists some x such that

y=f(x)=\log7x\\\Rightarrow 7x=10^y\\\Rightarrow x=10^y/7.

Since log x is defined for all real values of x greater than zero. So, the domain of the given function is

D={x|7x is a real number>0}={x|x is a real number>0}.

And range is given by

R={y|y=\log 7x}={y|y is a real number}.

Thus, the domain is the set of all positive real numbers and range is the set of all real numbers.

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Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer.
allochka39001 [22]

Answer:

No. See explanation below.

Step-by-step explanation:

Since the cards are being selected <u>without replacement,</u> every time we select a card, <u>the probability varies</u> (since there is one less card) and therefore, the probability doesn't remain the same for every trial and therefore, the probability of success changes for every trial.

It is because of this that this probability experiment doesn't represent a binomial experiment.

6 0
4 years ago
Simplify the expression<br> 3n+–9n+–8+–7n2
Lunna [17]

Answer: -7n^2-6n-8

Step-by-step explanation:

3 0
2 years ago
What is the antiderivative of 3x/((x-1)^2)
Maslowich

Answer:

\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

Step-by-step explanation:

Given

\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx

\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx

=3\cdot \int \frac{x}{\left(x-1\right)^2}dx

\mathrm{Apply\:u-substitution:}\:u=x-1

=3\cdot \int \frac{u+1}{u^2}du

\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}

=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx

=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)

as

\int \frac{1}{u}du=\ln \left|u\right|     ∵ \mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)

\int \frac{1}{u^2}du=-\frac{1}{u}        ∵     \mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1

so

=3\left(\ln \left|u\right|-\frac{1}{u}\right)

\mathrm{Substitute\:back}\:u=x-1

=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)

\mathrm{Add\:a\:constant\:to\:the\:solution}

=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

Therefore,

\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C

4 0
3 years ago
How me solve this problem please
Cerrena [4.2K]

Answer:

3 3/4

Step-by-step explanation:

The area of rectangle patio=5 5/8

Length=1 1/2

5 5/8 divided by 1 1/2= 3 3/4

8 0
2 years ago
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Sunny_sXe [5.5K]

Answer:

4 is the length of a side.

Step-by-step explanation:

16 divided by 4 equals 4

5 0
3 years ago
Read 2 more answers
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