Answer:
f finally
Step-by-step explanation:
hope it will helps you
From what I can tell, this can't be simplified, because there are no factors of 42 that are perfect squares. I would leave it as the square root of 42.
Answer:
The distance of the plane from the base of the tower is 25.5 foot.
Step-by-step explanation:
As given
Max is in a control tower at a small airport.
He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.
Now by using the trigonometric identity.
![tan\theta = \frac{Perpendicular}{Base}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7BPerpendicular%7D%7BBase%7D)
As shown in the figure given below
Perpendicular = CB
Base = AC = 50 feet
![\theta = 27^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2027%5E%7B%5Ccirc%7D)
Put in the identity.
![tan\ 27^{\circ} = \frac{CB}{AC}](https://tex.z-dn.net/?f=tan%5C%2027%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7BCB%7D%7BAC%7D)
![tan\ 27^{\circ} = \frac{CB}{50}](https://tex.z-dn.net/?f=tan%5C%2027%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7BCB%7D%7B50%7D)
![tan\ 27^{\circ} = 0.51\ (Approx)](https://tex.z-dn.net/?f=tan%5C%2027%5E%7B%5Ccirc%7D%20%3D%200.51%5C%20%28Approx%29)
Put in the above
![0.51 = \frac{CB}{50}](https://tex.z-dn.net/?f=0.51%20%3D%20%5Cfrac%7BCB%7D%7B50%7D)
CB = 0.51 × 50
CB = 25.5 foot
Therefore the distance of the plane from the base of the tower is 25.5 foot.
2(b+3) = 2
2b + 6 = 2 ( -6 )
2b = -4 ( / 2)
b = -2