A) I would make the positive integer x and then form an equation.
x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6
Since the question asks for a positive integer the answer is 7.
B) two positive numbers x and y.
X - y = 3
x^2 + y^2 = 117
Use these simultaneous equations to figure out each number.
Rearrange the first equation
x = y + 3
Then substitute it into the second equation.
(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)
This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.
Use y to find x
x = y + 3
x = 6 + 3
x = 9
So the answers are x = 9 and y = 6.
It would be A=18 because of the equation a^2+b^2=c^2.
By finding like denominators, you can add the fractions on each side. Then, compare by cross multiplying.
Answer:
Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.
Step-by-step explanation:
Number of apples in Bowl A = 6
Number of mangoes in Bowl B = 8
Difference in apples = 8 - 6 = 2
So, Bowl B contains 2 apples more than Bowl A.
Number of mangoes in Bowl A = 3
Number of mangoes in Bowl B =2
Difference in mangoes = 3 - 2 = 1
So, Bowl A contains 1 mango more than Bowl B.
Answer:
X= 114
I don’t know what y is labeling so I won’t be able to help there sorry
