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Thepotemich [5.8K]
3 years ago
12

If all direct materials are added at the end of the production process, and the units have made it 50% of the way through the pr

oduction process, then the percentage completion for direct materials is:A. 0%B. 100%.C. 50%D. None of the above.
Mathematics
1 answer:
ella [17]3 years ago
8 0

Answer:

Answer:option B  100%

Step-by-step explanation:

Since direct materials are added into production process at the end,so it will be more likely to be 100% completed.

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Margot is trying to decide between cable and satellite TV. Cable has a package of $49.99 a month for the basic package, plus $9.
VashaNatasha [74]
The cost of cable (c) in terms of months (m) is
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The cost of satellite TV (s) in terms of months is
  s = 125.00 +49.95m

The difference in price is ...
  s - c = (125 +49.95m) -(59.89m)
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This number is positive, which means ...
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At 24 months, the difference in price is
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A graph of the costs shows a cross-over at 12.5 months. Until then, the Cable provider is less expensive. Over terms longer than that, the Satellite TV provider is less expensive.

3 0
3 years ago
A. 4,-4<br> B. 2,-5<br> C.0,6<br> D.-2,5<br> Which would it be?
kipiarov [429]

Answer:

A

Step-by-step explanation:

If we insert the original coordinates into the problem, we will find the answer.

(2+2, 1-5)

so, once solved

(4, -4)

remember, adding to X means moving the point right, subtracting to X means moving left.

Adding to Y means moving the point up, subtracting to Y means moving down.

6 0
2 years ago
When does the price of an item increase?
Mrrafil [7]

Answer:

B

Step-by-step explanation:

Tell me if you need an explanation

3 0
3 years ago
I need help pleaseee
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6 0
2 years ago
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Given sin x = -4/5 and x is in quadrant 3, what is the value of tan x/2
love history [14]

bearing in mind that, on the III Quadrant, sine as well as cosine are both negative, and that hypotenuse is never negative, so, if the sine is -4/5, the negative number must be the numerator, so sin(x) = (-4)/5.


\bf sin(x)=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-4)^2}=a\implies \pm\sqrt{9}=a\implies \pm 3=a \\\\\\ \stackrel{III~Quadrant}{-3=a}~\hfill cos(x)=\cfrac{\stackrel{adjacent}{-3}}{\stackrel{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill

\bf tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}\qquad \leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\[-0.35em] ~\dotfill

\bf tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{1-\frac{3}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{\frac{2}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{5}\cdot \cfrac{5}{2} \\\\\\ tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{2}\cdot \cfrac{5}{5}\implies tan\left( \cfrac{x}{2} \right)=-2

4 0
3 years ago
Read 2 more answers
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