Let “n” represent the least of the odd numbers. Then the next two will be:
n + 2 and n + 4 that their sum is 159.
n + (n + 2) + (n + 4) = 159
3n + 6 = 159
3n = 153
n = 51
And to check: 51 + 53 + 55 = 159
Answer:
1 times 1 is 1
2 times 1 is 2
Your question is not very clear.
Step-by-step explanation:
p+(p*(33/100))+50
It doesn't really need the parentheses around the fraction. I just did that to show you to multiply p by the fraction as a whole instead of just the numerator. It does however need the parentheses around the 'p times the fraction' bit. Good luck. Hope this helps. Sorry if it doesn't.
8B and 10 not sure probably centre??
