x = total amount of gumballs
let's start subtracting the balls she's giving away
and we also know that after all that has been subtracted, she's only left with 5, so we can say that
Answer:
C is the closest.,
Step-by-step explanation:
I am assuming that the 2 trapezoids CBEF and EFDA are similar (they are similar if the 3 horizontal lines are parallel).
Corresponding sides are in the same ratio , so:
3.4 / EF = EF / 7.6
EF^2 = 3.4 * 7.6 = 25.84
EF = 5.08
C is not continuous.
Continuous functions have connected graphs; this indicates that every possible value of x has a value of y associated with it. In this case, that says that every possible radius measurement has a number of tennis balls associated with it. The problem with this is that we cannot have a fractional part of a tennis ball, so it is not continuous.
<span><span> 15x2y2+3x3y+75x4</span> </span>Final result :<span> 3x2 • (25x2 + xy + 5y2)
</span>
Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> (((15•(x2))•(y2))+((3•(x3))•y))+(3•52x4)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> (((15•(x2))•(y2))+(3x3•y))+(3•52x4)
</span><span> Step 3 :</span></span><span>Equation at the end of step 3 :</span><span> (((3•5x2) • y2) + 3x3y) + (3•52x4)
</span><span>Step 4 :</span><span>Step 5 :</span>Pulling out like terms :
<span> 5.1 </span> Pull out like factors :
<span> 75x4 + 3x3y + 15x2y2</span> = <span> 3x2 • (25x2 + xy + 5y2)</span>
Trying to factor a multi variable polynomial :
<span> 5.2 </span> Factoring <span> 25x2 + xy + 5y2</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
Final result :<span> 3x2 • (25x2 + xy + 5y2)
</span><span>
</span>
The correct box plot will have the "whiskers" extending to 24 and 49. The first quartile will be around 28.5 and the third quartile will be around 41.8. The median will be at 34.
**your question didn't include the box plots to choose from, so use this information to find which one it is :)
