Just need the answer

Evaluate the iterated integral 2 0 2 x sin(y2) dy dx. SOLUTION If we try to evaluate the integral as it stands, we are faced wit

nignag [31]

Answer:

Step-by-step explanation:

Given that:

$\int^2_0 \int^2_x \ sin (y^2) \ dy dx \\ \\ \text{Using backward equation; we have:} \\ \\ \int^2_0\int^2_0 sin(y^2) \ dy \ dx = \int \int_o \ sin(y^2) \ dA \\ \\ where; \\ \\ D= \Big\{ (x,y) | }0 \le x \le 2, x \le y \le 2 \Big\}$

$\text{Sketching this region; the alternative description of D is:} \\ D= \Big\{ (x,y) | }0 \le y \le 2, 0 \le x \le y \Big\}$

$\text{Now, above equation gives room for double integral in reverse order;}$

$\int^2_0 \int^2_0 \ sin (y^2) dy dx = \int \int _o \ sin (y^2) \ dA \\ \\ = \int^2_o \int^y_o \ sin (y^2) \ dx \ dy \\ \\ = \int^2_o \Big [x sin (y^2) \Big] ^{x=y}_{x=o} \ dy \\ \\= \int^2_0 ( y -0) \ sin (y^2) \ dy \\ \\ = \int^2_0 y \ sin (y^2) \ dy \\ \\ y^2 = U \\ \\ 2y \ dy = du \\ \\ = \dfrac{1}{2} \int ^2 _ 0 \ sin (U) \ du \\ \\ = - \dfrac{1}{2} \Big [cos \ U \Big]^2_o \\ \\ = - \dfrac{1}{2} \Big [cos \ (y^2) \Big]^2_o \\ \\ = - \dfrac{1}{2} cos (4) + \dfrac{1}{2} cos (0) \\ \\$

$= - \dfrac{1}{2} cos (4) + \dfrac{1}{2} (1) \\ \\ = \dfrac{1}{2}\Big [1- cos (4) \Big] \\ \\ = \mathbf{0.82682}$

5 0

2 years ago

Solve 2x2 + 5x = 12

aliya0001 [1]

2x2+5x=12, 2x+5x=7x, 12+2=14, 7x/7=14/7, x=2

4 0

3 years ago

This makes no sense, help pls

stiv31 [10]

Please mark me branliest!

**Answer**

16 if you want exact, 20 if you want a little over.

**Explanation**

So check this... it's $50 per student that attends the camp, right?

(Nod if you're with me.)

The dude buys 5 dozen donuts for 16 days. 50 x 16 = 800

5 dozen is the same as 50 donuts.

You multiply to get the total amount of donuts he buys in the total days (16).

Each 10 donuts costs 10 dollars.

If the dude buys 800 donuts it cost him $800.

And it costs 50 dollars for someone to go to camp.

So you divide 800/50 = 16 students

Now the problem says "In order to break even" I'm not sure what that means. But I'm assuming it doesn't want 16 then, because the price of 16 students would be the same (even) as the price of donuts that Mr. Brook buys. In that case it would be 20.

You are very welcome!!

8 0

2 years ago

Plz ANWSER and make sure it’s in decimal form, plz show ur work <br> Overdue will mark brainest!

kari74 [83]

Answer:

Step-by-step explanation:The model will be of length 0.4 ft and the width being 0.28 feet

Step-by-step explanation:

Step 1.We know that the length of the building is 200 feet, and that the width of the building is 140 feet.

Step 2. the question tells us that "a 1/500 model is built of the building", meaning the problem wants to create a model using the ratio 1 feet for each 500 feet.

Step 3.So now to find the length and width of the model, we need to divide the given sides by 500.

Step 4. Side length of the Model = 200/500 = 2/5 = 0.4 feet

Step 5. Side width of the Model = 140/500 = 14/50 = 0.28 feet

There for giving us our final answer... "The model will be of length 0.4 feet and width 0.28 feet."

Hope I could help! :)

6 0

2 years ago

Read 2 more answers

Put these in order from Smallest- 5^2, 2^4, 3^3, 1^8

Marysya12 [62]

Your answer is alredy in order

4 0

2 years ago

Read 2 more answers