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3 years ago

Does anyone Know what y = 1.6x + 48?

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer:

49.6 is what y is equal to

Step-by-step explanation

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Linear equation for (-5,3) and (-1,-1)

Alex787 [66]

Answer:

y = -x - 2

Step-by-step explanation:

y = mx + c

m = (-1-3)/(-1-(-5)) = -4/4 = -1

y = -x + c

(-1,-1)

-1 = -(-1) + c

c = -2

y = -x - 2

6 0

4 years ago

Hi i need help with this

ICE Princess25 [194]

The range would be [-4, infinity) because range is the y-value. The lowest y-value is -4. The greatest y-value goes up to infinity.

7 0

3 years ago

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$