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2 years ago

How to find the X with the midsegment theorem

Mathematics

2 answers:

Rus_ich [418]2 years ago

7 0

X=(1/2)(20)=10
Here is the answer

gtnhenbr [62]2 years ago

6 0

Half of 20 the line is in the middle of the triangle

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Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help

natta225 [31]

Answer:

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a_{1}(r^n-1) }{r-1}$

Here a₁ = 4 and r = - 3, thus

$S_{6}$ = $\frac{4((-3)^6-1)}{-3-1}$

= $\frac{4(729-1)}{-4}$ = - (729 - 1) = - 728 → C

6 0

2 years ago

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Sonja [21]

B) The side opposite the 60° angle is longer than the side opposite the 30° angle

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2 years ago

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antoniya [11.8K]

Answer:

The answer will be 24

Step-by-step explanation:

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2 years ago

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Help ASAP plz!!

marusya05 [52]

Answer: D
(0,-4) (12,6)
slope= 10/12
slope== 5/6
y=5/6x+b
-4=0+b
b=-4
the equation of the line is
y=5/6x-4

6 0

2 years ago

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068