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exis [7]
3 years ago
13

In the inequality 1/ 2 x - 6 > 10, x represents Todd's age. Which phrase most accurately describes Todd's age? A) Todd is old

er than 32. B) Todd is younger than 32. C) Todd is exactly 32 years old. D) Todd is 32 years old or older.
Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

Option A) Todd is older than 32

Step-by-step explanation:

we have

\frac{1}{2}x-6>10

Solve for x

Adds 6 both sides

\frac{1}{2}x>10+6\\\\\frac{1}{2}x>16

Multiply by 2 both sides

x>32

so

Todd's age is greater than 32

therefore

Todd is older than 32

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Chantelle has signed up for hockey. Her parents set a limit of $400 for costs for the season. It costs $250 to sign up and $5 fo
VLD [36.1K]

Answer:

30 times

Step-by-step explanation:

$400 minus $250=$150

$150 divided by $5=30 so she can go 30 times

3 0
3 years ago
You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel
erica [24]

Answer:

a)

P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357

P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034

P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377

P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015

P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

100 welders, so N = 100

Sample of 15, so n = 15

In total, 5 defective, so k = 5

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357

P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034

P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377

P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015

P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

(b) Determine the probability that there are at least 4 defective welders in the sample?

P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154

0.154% probability that there are at least 4 defective welders in the sample

5 0
3 years ago
For which value(s) of the constant k is the circle x² + (y − k)² = 16 tangent to the line y = 3?
STALIN [3.7K]

<em>Answer:</em>

<em />

<em>Step-by-step explanation:Let us find points of intersection of line  </em>

<em>3 </em>

<em>x </em>

<em>+ </em>

<em>4 </em>

<em>y </em>

<em>− </em>

<em>k </em>

<em>= </em>

<em>0 </em>

<em> and circle  </em>

<em>x </em>

<em>2 </em>

<em>+ </em>

<em>y </em>

<em>2 </em>

<em>= </em>

<em>16 </em>

<em>. We can do this by putting value of  </em>

<em>y </em>

<em> from first equation i.e.  </em>

<em>y </em>

<em>= </em>

<em>k </em>

<em>− </em>

<em>3 </em>

<em>x </em>

<em>4 </em>

<em> and we get </em>

<em> </em>

<em>x </em>

<em>2 </em>

<em>+ </em>

<em>( </em>

<em>k </em>

<em>− </em>

<em>3 </em>

<em>x </em>

<em>) </em>

<em>2 </em>

<em>16 </em>

<em>= </em>

<em>16 </em>

<em> </em>

<em>or  </em>

<em>16 </em>

<em>x </em>

<em>2 </em>

<em>+ </em>

<em>k </em>

<em>2 </em>

<em>+ </em>

<em>9 </em>

<em>x </em>

<em>2 </em>

<em>− </em>

<em>6 </em>

<em>k </em>

<em>x </em>

<em>= </em>

<em>256 </em>

<em> </em>

<em>i.e.  </em>

<em>25 </em>

<em>x </em>

<em>2 </em>

<em>− </em>

<em>6 </em>

<em>k </em>

<em>x </em>

<em>+ </em>

<em>k </em>

<em>2 </em>

<em>− </em>

<em>256 </em>

<em>= </em>

<em>0 </em>

<em> </em>

<em>This would give two values of  </em>

<em>x </em>

<em> and corresponding two values of  </em>

<em>y </em>

<em> i.e. two points. But tangent cuts the circle in only at one point. This will be so when discriminant is zero i.e. </em>

<em> </em>

<em>( </em>

<em>− </em>

<em>6 </em>

<em>k </em>

<em>) </em>

<em>2 </em>

<em>− </em>

<em>4 </em>

<em>⋅ </em>

<em>25 </em>

<em>⋅ </em>

<em>( </em>

<em>k </em>

<em>2 </em>

<em>− </em>

<em>256 </em>

<em>) </em>

<em>= </em>

<em>0 </em>

<em> </em>

<em>or  </em>

<em>− </em>

<em>64 </em>

<em>k </em>

<em>2 </em>

<em>+ </em>

<em>25600 </em>

<em>= </em>

<em>0 </em>

<em> or  </em>

<em>k </em>

<em>= </em>

<em>± </em>

<em>20 </em>

<em> </em>

<em>graph{(x^2+y^2-16)(3x+4y-20)(3x+4y+20)=0 [-10, 10, -5, 5]}</em>

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