Second grade Solve using algorithm. Draw chips and bundle when you can

Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0

3 years ago

How do you convert 1.024242424 to a fraction

AnnyKZ [126]

The number before the decimal and the first number after the decimal and the last number

4 0

3 years ago

Mathematics

Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

4 0

1 year ago

Triangle ABC is isosceles.

motikmotik

Answer:

You need to understand construction chapter to answer your question.

3 0

3 years ago

A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f

max2010maxim [7]

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

x = kilograms of the 40% chocolate.
y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

8 0

1 year ago