Hello,
Let's assume n,n+1,n+2,n+3,n+4 the 5 numbers
n+(n+1)+...+(n+4)=5n+10=265
5n=265-10
5n=255
n=51
The 5th number is 51+4=55
<h2>
Greetings!</h2>
Answer:
y = 
and x = 
Step-by-step explanation:
To solve simultaneous equations, you need to have the number in front of both x's or y's the same. (signs doesn't matter)
To get -x to -10x we simply need to multiply the first equation by 10:
-x * 10 = -10x
-9y * 10 = -90y
16 * 10 = 160
-10x - 90y = 160
Now we can add the two equations:
-10x + 10x = 0
-90y + 20y = -70y
160 + 20 = 180
-70y = 180
70y = -180
7y = -18
y =
Now plug into the second equation:
10x + 20() = 20
10x - 
= 20
Move the over to the other side, making it a positive:
10x = 20 +
10x = 
Divide both sides by 10:
x =
So y = and x =
<h2>Hope this helps!</h2>
Answer:
C
Step-by-step explanation:
We are given that FGH is a triangle, which means that...
Angle F + Angle G + Angle H = 180
Start by substituting the given angle measurements into the equation:
4x+2+13x-7+3x+5=180
Combine like terms
20x=180
Divide both sides by 20 to isolate x
x=9
Plug 9 back in for x to solve for each angle
Angle F = 4(9)+2=36+2=38
Angle G = 13(9)-7=117-7=110
Angle H = 3(9)+5=27+5=32
<h3>Answer:</h3>
A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
<h3>Explanation:</h3>
The sum of angles in ∆ABC is 180°, so ...
... (2x -2) + (2x +2) + (5x) = 180
... 9x = 180
... x = 20
and the angles of ∆ABC are ∠A = 38°, ∠B = 42°, ∠C = 100°.
___
The sum of angles of ∆A'B'C' is 180°, so ...
... (58 -x) +(3x -18) +(120 -x) = 180
... x +160 = 180
... x = 20
and ∠A' = 38°, ∠B' = 42°, ∠C' = 100°.
_____
The values of angle measures of ∆ABC match those of ∆A'B'C', so we can conclude ...
... A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
An=A(n-1)-5.9
The next two are -18.5 and -24.4
You subtract 5.9 from the previous number to get the new number
