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3 years ago

What would a persons speed if they travelled 394 meters in 94 seconds?

Mathematics

1 answer:

VladimirAG [237]3 years ago

7 0

Distance = speed* time

distance = 394meters, time = 94 seconds

speed = distance/time
= 394/94
= 4.191 m/s

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What is 3 5 as a percentage?

Ratling [72]

Your answer will be 60%

Have a nice day

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3 years ago

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HELP ALGEBRA IS KILLING ME IMAGE IS BELOW

djyliett [7]

Answer:

58240

Step-by-step explanation:

1425 ------ 45600

1820 ------ x

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45600*1820 = 82992000

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3 years ago

By copying and completing the working below, work out 3 + 1 16 Give your answer as a fraction in its simplest form.

Ksenya-84 [330]

Answer:

Assuming the question is: 3 + 1 16 [I see no "working below."

Step-by-step explanation:

3 + 1 16

48/16 + (16/16 + 1/16) [Make all numbers into fractions using 16 as the denominator. E.g. 48/16 = 3.

Add: 48/16 + (16/16 + 1/16)

(48+16+1)/16

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7 0

3 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

6 0

3 years ago

In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°

djyliett [7]

Answer:

14.2cm

Step-by-step explanation:

Complete question:

In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°.

Rounded to the nearest tenth of a centimeter, what is the length of arc LMN?

Find the diagram attached

arc LN= arc LM + arc MN

First we need to get the arc MN

length of an arc = theta/360 * 2πr

length of arc MN = 75/360 * 2(3.14)(6)

length of arc MN = 0.20833*37.68

length of arc MN = 7.85

Hence;

arc LN = 6.3 + 7.85

arc LN = 14.15cm

Hence the length of arc LN is 14.2cm

8 0

3 years ago