All categories

2 years ago

Joshua eat 3/8 of a pizza trevor eats 1/2 of a pizza how much of the pizza did they eat?

Mathematics

1 answer:

Elina [12.6K]2 years ago

5 0

Answer:

7/8ths of a pizza.

Step-by-step explanation:

3/8 + 1/2

Find the LCD and then combine.

7/8 in exact form, and 0.875 as a decimal.

You might be interested in

Please help me i am desperate please (1/3)

Sergeu [11.5K]

I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?

I'll do the first page.

Right triangle, opposite side of 10, adjacent side of 21,

tan x = opp/adj = 10/21

x = arctan 10/21 = 25.46°

Answer: 25

cos x = adj / hyp = 10/14

x = arccos 10/14 = 44.42°

Answer: 44

tan x = opp/adj = 12/24 = 1/2

x = arctan 1/2 = 26.57°

Answer: 27

tan x = 31/32

x = arctan 31/32 = 44.09°

Answer: 44

10)

x = arctan 10/27 = 20.32°

Answer: 20

8 0

3 years ago

A 10-ounce container of chocolate chips can be used to make 4 desserts.

Mademuasel [1]

Answer:

10/4 =10/4 ounces

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is 3m - 9/2,,,,,,,, Please help i need it now

Damm [24]

It would be $\frac{6m-9}{2}$ .

4 0

3 years ago

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

the answer Part a) is

the speed is equal to $3.5\frac{m}{sec}$

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

the answer Part b) is

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

the answer Part c) is

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

7 0

3 years ago

Read 2 more answers

- An experiment consists of rolling two fair

KengaRu [80]

Answer:

Step-by-step explanation:

Each time two cubes are rolled, the sum can be a number from 2 (rolling 1 and 1) to 12 (rolling 6 and 6). It is impossible to get a sum of more than 12, so there is zero probability of getting a sum of 47.

Answer: 0

7 0

3 years ago