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3 years ago

An Atlas moth has a wingspan of 11 inches. What is the wingspan of 26 Atlas moths?

Mathematics

1 answer:

Nady [450]3 years ago

8 0

Answer:

The wingspan of 26 atlas moths are <u>286</u> inches.

Step-by-step explanation:

Given:

An Atlas moth has a wingspan of 11 inches.

Now, to find the wingspan of 26 atlas moths.

So, we use unitary method:

As given an atlas wingspan has 11 inches.

Then for wingspan of 26 atlas we multiply it by 11 inches:

⇒ $26\times 11\ inches$

$=286\ inches.$

Therefore, the wingspan of 26 atlas moths are 286 inches.

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Which of the following are arithmetic sequences? Check all that apply.

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a c and d

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3 years ago

The tickets for a dance recital cost $5.00 for adults and $2.00 for children. If the total number of tickets sold was 295 and th

dem82 [27]

To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children

5a + 2c = 1,220
a + c = 295

a + c = 295
-c -c
a = 295 - c

5(295 - c) + 2c = 1,220
1,475 - 5c + 2c = 1,220
1,475 - 3c = 1,220

1,475 - 3c = 1,220
-1,475 -1,475
-3c = -255

-3c/-3 = -255/-3
c = 85

a + c = 295
a + 85 = 295
-85 -85
a = 210

210 adults attended the dance recital

Hope this helps!

6 0

3 years ago

A data set has a mean of x = 71 and a standard deviation of 11.6. Find the z-score for each of the following.

olchik [2.2K]

Answer:

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Step-by-step explanation:

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2 years ago

A square storage unit has a volume of 607.5 ft3. The height of the unit is 7.5 ft. What are the length and width of the storage

Eduardwww [97]

Answer:

9ft

Step-by-step explanation:

The base area of the storage is its volume divided by height

$A = \frac{V}{h} = \frac{607.5}{7.5} = 81 ft^2$

Since this base is a square, its length and width is of equal length, which is

$\sqrt{A} = \sqrt{81} = 9ft$

4 0

3 years ago

Read 2 more answers

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago