Answer:
P = 49°
R = 131°
Q = 114°
S = 66°
Step-by-step explanation:
in a quadrilateral inscribed in a circle, the opposite angles are always supplementary, meaning they add up to 150
we are given opposite angles P and R (S is not given so we can't use Q and S)
P+R = 180
5y+14 + 15y + 26 = 180
20y + 40 = 180
20y = 140
y = 7
so...
P = 5(7) + 14 = 35 + 14 = 49
R = 180-49 (since opposite angles in inscribed quadrilaterals are supplementary) = 131
Q = (7)^2 + 65 = 49 + 65 = 114
S = 180-114 = 66
Answer:
2.5
Step-by-step explanation:
Answer:
3 times
Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3
This means that the large diameter is 3 times the small one.
Hope this helps :)
There's only one step to solve this problem (that's if you're looking for it)
Because,
